Path lifting lemma

cosmos 17th October 2017 at 6:26pm
Covering

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Let p:EBp: E \to B be a Covering, with p(e0)=b0p(e_0) = b_0. Then any path f:[0,1]Bf: [0,1] \to B, with initial f(0)=b0f(0) = b_0, has a unique lifting to a path f~:[0,1]E\tilde{f}: [0,1] \to E such that f~(0)=e0\tilde{f}(0) = e_0.

Proof.