Simplicial homology

cosmos 29th October 2017 at 11:40am
Homology

Idea: decompose space into triangles, restrict attention to polyhedral cycles & boundaries

Delta-complex

Simplicial cycle

Simplicial 1-boundary

The group of chains of n-simplices of a Delta-complex of XX is Δn(X):=Z{eαn}\Delta_n(X) := \mathbb{Z} \langle\{e^n_\alpha\}\rangle

The Boundary map :Δn(X)Δn1(X)\partial: \Delta_n(X) \to \Delta_{n-1}(X). eαneαne_\alpha^n \mapsto \partial e_\alpha^n, where ([v0,...vn])=i(1)i[v0,...,vi^,...,vn]\partial([v_0,...v_n]) = \sum\limits_i (-1)^i [v_0,...,\hat{v_i},...,v_n], where viv_i are vertices and ^\hat{} means that we omit the vertex.

The group of n-cycles is

Zn(X):={zΔn(X)z=0}\mathbb{Z}_n(X) := \{ z \in \Delta_n(X) | \partial z = 0\}

The group of n-boundaries is

Bn(X):={bΔn(X)cΔn+1(X) s.t. c=b}B_n(X) := \{ b \in \Delta_n(X) | \exists c \in \Delta_{n+1}(X) \text{ s.t. } \partial c = b \}

The simplicial homology or Simplicial homology group of XX is

Hn(X):=Zn(X)Bn(X)H_n(X) := \frac{\mathbb{Z}_n(X)}{B_n(X)}

This is the Quotient group. Elements of this groups are Cosets of BnB_n and are called homology classes. Two cycles representing the same homology class are said to be homologous. This means that their difference is a boundary. The cycle and boundary groups can be described as the kernel and images of the boundary map:

The group of n-cycles is Zn:=Ker(n)Z_n:= Ker(\partial_n) (the kernel)

The group of n-boundaries is Bn:=Im(n+1)B_n:= Im(\partial_{n+1}) (the image)

For e.g. in case C22C11C0C_2 \to_{\partial_2} C_1 \to_{\partial_1} C_0 (eg in Hatcher), The homology group is then defined as above: the kernel of 1\partial_1 modulo the image of 2\partial_2 , or in other words, the 1 dimensional cycles modulo those that are boundaries (remember "modulo" for groups means that that two elements are equivalent if we can add/substract elements in the group of boundaries to get from one to the other (Quotient group). So the two sides of a boundary are equivalent because one can add/substract the boundary to get from one to the other.. Remember add/substract in the Free Abelian group sense for the Chain group.


Remains to show that it is independent of Delta-complex in the topological space, also invariant under Homotopy equivalent (stronger).


See book

A Chain complex is a sequence of Abelian groups with maps ...Ci2i1Ci1iCii+1Ci+1......\leftarrow C_{i-2} \leftarrow_{\partial_{i-1}} C_{i-1} \leftarrow_{\partial_i} C_i \leftarrow_{\partial_{i+1}} C_{i+1} \leftarrow ...

s.t. i1i=0\partial_{i-1}\partial_i = 0 i\forall i. "the boundary of a boundary is 00".