Cycle decomposition

cosmos 12th October 2017 at 11:09pm
Symmetric group

Definition

See Symmetric group

An important special case is a cycle. All disjoint cycles commute (disjoint refers to the fact that they cycle different elements). Theorem: All elements in the symmetric group can be written as a product of disjoint cycles. If the union of the supports of the cycles equals the {1...n}\{1...n\}, the decomposition is unique and we call it the Cycle decomposition

Proof The support of the cycles in the cycle decompositoin of permutation σ\sigma are the Group orbits generated by σ\sigma acting on the elements of {1...n}\{1...n\} (where the group action is just by interpreting σ\sigma as a bijection). Corollary: every element in symmetric group can be written as a product of Transpositions, because any cycle is a product of transpositions.

The Conjugacy class of an element in symmetric group is determined by the length of the cycles in the cycle decomposition. So there is a 1-1 correspondence between conjugacy classes and paritions of the set [n].

Lemma. Two permutations are conjugated if and only if they have the same type.

Corollary. The number of conjugacy classes of S_n is equal to the number of partitions of [n], which is 2n2^n.

Sign of a permutation